32^x-1=4^x+5

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Solution for 32^x-1=4^x+5 equation: 



32^x-1=4^x+5

We move all terms to the left:

32^x-1-(4^x+5)=0

We get rid of parentheses

32^x-4^x-5-1=0

We add all the numbers together, and all the variables

32^x-4^x-6=0

We move all terms containing x to the left, all other terms to the right

32^x-4^x=6

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